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	<title>Comments on: PHP Tutorial : Results Pagination</title>
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	<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/</link>
	<description>PHP tutorials - Examples of the most useful scripts</description>
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		<title>By: admin</title>
		<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/comment-page-1/#comment-5699</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Sat, 28 Nov 2009 20:20:17 +0000</pubDate>
		<guid isPermaLink="false">http://readytousesolutions.com/phpblog/?p=284#comment-5699</guid>
		<description>These errors means that the query was not successful. The code snippet in this post does not make any error checking and even suppresses some errors. Are you sure the MySQL DB is properly setup? 

You may want to try to type the same query in MyPHPadmin and rule out any MySQL problem. Also, remove the @ sign in the code. This will let PHP to output the errors as they happen and provide you with more insight in the problem.</description>
		<content:encoded><![CDATA[<p>These errors means that the query was not successful. The code snippet in this post does not make any error checking and even suppresses some errors. Are you sure the MySQL DB is properly setup? </p>
<p>You may want to try to type the same query in MyPHPadmin and rule out any MySQL problem. Also, remove the @ sign in the code. This will let PHP to output the errors as they happen and provide you with more insight in the problem.</p>
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		<title>By: igwe</title>
		<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/comment-page-1/#comment-5448</link>
		<dc:creator>igwe</dc:creator>
		<pubDate>Sat, 21 Nov 2009 06:45:40 +0000</pubDate>
		<guid isPermaLink="false">http://readytousesolutions.com/phpblog/?p=284#comment-5448</guid>
		<description>This is the error I am getting 


Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\phpfiles\pagination.php on line 16

viewing 1 - of entries
pages: 

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\phpfiles\pagination.php on line 57


please any help will be appreciated.</description>
		<content:encoded><![CDATA[<p>This is the error I am getting </p>
<p>Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\phpfiles\pagination.php on line 16</p>
<p>viewing 1 &#8211; of entries<br />
pages: </p>
<p>Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\phpfiles\pagination.php on line 57</p>
<p>please any help will be appreciated.</p>
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	<item>
		<title>By: admin</title>
		<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/comment-page-1/#comment-4829</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Wed, 04 Nov 2009 13:39:05 +0000</pubDate>
		<guid isPermaLink="false">http://readytousesolutions.com/phpblog/?p=284#comment-4829</guid>
		<description>Thanks for pointing out the missing parenthesis (now fixed), there are also some extra greater than signs before control statements. I have to look at the plugin that formats the code, as it seems not to work properly.

I had a look at the code, and it should work. Try removing the @ sign in front of the mysql fetch function, and see if an error arises. Will have a deeper look at the code and report back.</description>
		<content:encoded><![CDATA[<p>Thanks for pointing out the missing parenthesis (now fixed), there are also some extra greater than signs before control statements. I have to look at the plugin that formats the code, as it seems not to work properly.</p>
<p>I had a look at the code, and it should work. Try removing the @ sign in front of the mysql fetch function, and see if an error arises. Will have a deeper look at the code and report back.</p>
]]></content:encoded>
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	<item>
		<title>By: Roy</title>
		<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/comment-page-1/#comment-4353</link>
		<dc:creator>Roy</dc:creator>
		<pubDate>Tue, 27 Oct 2009 03:42:40 +0000</pubDate>
		<guid isPermaLink="false">http://readytousesolutions.com/phpblog/?p=284#comment-4353</guid>
		<description>Greetings,
there is a missing ) on the isset line.  Thanks for the tutorial but clicking on next or last doesn&#039;t display anything.  I tried using self instead of pagename and got error messages.  How do I get the pages beyond page one to display the data?</description>
		<content:encoded><![CDATA[<p>Greetings,<br />
there is a missing ) on the isset line.  Thanks for the tutorial but clicking on next or last doesn&#8217;t display anything.  I tried using self instead of pagename and got error messages.  How do I get the pages beyond page one to display the data?</p>
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	<item>
		<title>By: XkiD &#124; PHP Tutorial : Results Pagination &#124; blog.xkid.ro</title>
		<link>http://readytousesolutions.com/phpblog/php-tutorial-results-pagination/comment-page-1/#comment-2436</link>
		<dc:creator>XkiD &#124; PHP Tutorial : Results Pagination &#124; blog.xkid.ro</dc:creator>
		<pubDate>Mon, 15 Jun 2009 05:40:10 +0000</pubDate>
		<guid isPermaLink="false">http://readytousesolutions.com/phpblog/?p=284#comment-2436</guid>
		<description>[...] the original post here:  PHP Tutorial : Results Pagination      Posted in PHP &#124;  Tags: database, image-below, name-on-every, page-numbers-, PHP, [...]</description>
		<content:encoded><![CDATA[<p>[...] the original post here:  PHP Tutorial : Results Pagination      Posted in PHP |  Tags: database, image-below, name-on-every, page-numbers-, PHP, [...]</p>
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